How to create even spacing for clones in Scratch
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LayoutMaster_Dev
Posted on January 18, 2025 • Intermediate
🃏 Need help with even spacing for clones
Hello everyone! I’m working on a card game project and I need to figure out how to space “n” clones evenly along the x-axis. The clones should be evenly distributed within a specific range (x1, x2), and the spacing should adapt based on how many clones there are.
I want to achieve something similar to how the game Balatro spaces cards in your hand - where the cards automatically adjust their spacing based on how many you have. The more cards, the closer they get, but they’re always evenly distributed.
Here’s what I need:
- Even spacing between all clones
- Clones fit within a defined range (x1 to x2)
- Automatic adjustment based on number of clones
- Clean, professional-looking layout
Any help with the math or Scratch implementation would be greatly appreciated! 🙏
AlgorithmWizard
Replied 30 minutes later • ⭐ Best Answer
Perfect question @LayoutMaster_Dev! This is a classic linear interpolation problem. Here’s exactly how to implement even spacing for your clones:
📐 Even Spacing Algorithm Flow
Here’s how the spacing calculation works:
🔧 Step 1: Set Up Variables
First, create the necessary variables for your spacing system:
when flag clicked set [x1 v] to [-200] // Left boundary set [x2 v] to [200] // Right boundary set [number of clones v] to [5] // How many clones you want set [clone index v] to [0] // Current clone being positioned
📏 Step 2: The Core Spacing Formula
This is the magic formula for even spacing (linear interpolation):
// For each clone, calculate its x position set [clone x position v] to ((x1) + (((clone index) / ((number of clones) - (1))) * ((x2) - (x1)))) // Set the clone's position go to x: (clone x position) y: [0]
🃏 Step 3: Complete Clone Creation System
Here’s the full implementation for creating evenly spaced clones:
when flag clicked delete all clones of [myself v] // Handle special case: only 1 clone if <(number of clones) = [1]> then set [clone x position v] to (((x1) + (x2)) / [2]) // Center position go to x: (clone x position) y: [0] create clone of [myself v] else // Create multiple clones with even spacing set [clone index v] to [0] repeat (number of clones) set [clone x position v] to ((x1) + (((clone index) / ((number of clones) - (1))) * ((x2) - (x1)))) go to x: (clone x position) y: [0] create clone of [myself v] change [clone index v] by [1] end end
🎮 Step 4: Dynamic Adjustment System
Make it responsive to changing numbers of clones:
// When number of clones changes when I receive [update layout v] delete all clones of [myself v] // Recalculate positions set [clone index v] to [0] repeat (number of clones) set [clone x position v] to ((x1) + (((clone index) / ((number of clones) - (1))) * ((x2) - (x1)))) go to x: (clone x position) y: [0] create clone of [myself v] change [clone index v] by [1] end
🎨 Step 5: Advanced Features
Add these enhancements for professional card layouts:
📐 Curved Arrangement (Like Real Cards)
// Add slight curve to card arrangement set [curve factor v] to [0.3] set [center x v] to (((x1) + (x2)) / [2]) // Calculate curved position set [distance from center v] to ([abs v] of ((clone x position) - (center x))) set [curve offset v] to ((distance from center) * (curve factor)) // Apply curve to y position go to x: (clone x position) y: (curve offset)
🔄 Overlap Prevention
// Ensure minimum spacing between clones set [min spacing v] to [30] // Minimum pixels between clones set [available width v] to ((x2) - (x1)) set [required width v] to ((number of clones) * (min spacing)) if <(required width) > (available width)> then // Adjust boundaries to fit all clones set [x1 v] to ((center x) - ((required width) / [2])) set [x2 v] to ((center x) + ((required width) / [2])) end
🎯 Step 6: Real-World Example
Here’s how it works with actual numbers:
- 5 cards, range -200 to 200:
- Card 0: -200 + (0/4) × 400 = -200
- Card 1: -200 + (1/4) × 400 = -100
- Card 2: -200 + (2/4) × 400 = 0
- Card 3: -200 + (3/4) × 400 = 100
- Card 4: -200 + (4/4) × 400 = 200
🔍 Troubleshooting Tips
- Cards overlapping: Increase your range (x2 - x1) or reduce number of clones
- Uneven spacing: Make sure you’re using (n-1) in the denominator, not n
- Cards outside bounds: Check that x1 < x2 and both are within stage limits
- Single card positioning: Use center formula: (x1 + x2) / 2
This linear interpolation method is the same technique used in professional game engines and is perfect for card games, inventory systems, and any UI that needs even spacing!
Vibelf_Community
Pinned Message • Moderator
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📚 Related Algorithm Topics
- Advanced clone management techniques
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- Mathematical functions in game design
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